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Table 4 C. elegans duplicate gene pairs with at least partially redundant functions

From: Combinatorial RNA interference in Caenorhabditis elegans reveals that redundancy between gene duplicates can be maintained for more than 80 million years of evolution

Interaction Gene1 + Gene2 Gene1 Gene2 Gene1 + 2 p value
  BS ES BS ES BS ES BS ES
pab-1 + pab-2 15 100 88 100 0 ns 1.9 × 10-04 ns
rpl-25.2 + rpl-25.1 6 50 17 63 0 ns 3.6 × 10-04 ns
ptr-2 + ptr-10 a 53 a 98 a ns a ns
unc-78 + tag-216 85 96 98 97 0 ns 6.4 × 10-15 ns
rab-8 + rab-10 87 98 70 96 1 ns 7.3 × 10-05 ns
B0495.2 + ZC504.3 84 99 97 99 2 55 6.3 × 10-09 2.9 × 10-03
rpa-2 + C37A2.7 67 74 50 81 1 ns 1.9 × 10-07 ns
C28H8.4 + erd-2 93 95 86 94 10 10 5.6 × 10-08 2.2 × 10-15
lin-12 + glp-1 90 88 99 83 16 75 1.2 × 10-13 7.3 × 10-01
C13G3.3 + W08G11.4 73 94 80 97 17 89 1.6 × 10-06 3.5 × 10-01
lin-53 + rba-1 74 63 48 5 16 75 1.1 × 10-02 7.3 × 10-17
Y53C12A.4 + R02E12.2 84 81 78 87 32 75 1.3 × 10-03 6.9 × 10-01
F37C12.7 + acs-17 95 100 77 98 44 73 9.4 × 10-03 4.2 × 10-06
C05G5.4 + F23H11.3 96 100 94 98 58 72 5.1 × 10-06 1.5 × 10-08
elt-6 + egl-18 100 97 82 88 63 73 4.0 × 10-02 6.3 × 10-03
dsh-1 + dsh-2 97 98 75 54 58 17 1.6 × 10-02 1.1 × 10-11
  1. C. elegans duplicate gene pairs (Interaction Gene1 + Gene2) displaying synthetic phenotypic effects upon combinatorial RNA interference (RNAi) in the RNAi-hypersensitive strain rrf-3 [19] are listed. Numbers shown are percentages of average wild-type brood size (BS) and embryonic survival (ES) rates for each gene individually (Gene1 or Gene2) as well as for duplicate gene pairs (Gene1 + 2), and are the arithmetic mean of two independent biological repeats. p values were assigned using a Student's t-test. aNote that combinatorial RNAi against the duplicate gene pair ptr-2 + ptr-10 resulted in an increased number of first generation larval growth arrested worms, rather than in reduced brood size; fraction of population which is wild-type (does not arrest at an early larval stage): 70% (ptr-2), 100% (ptr-10), 0% (ptr-2 + ptr-10), p = 7.4 × 10-09. ns, given phenotype could not be scored.